9744 Train Route
S. No | Station Name & Code | Arrives | Departs | Halt Time | Distance | Avg. Delay | Day |
---|---|---|---|---|---|---|---|
1 | Anupgarh - APH | Start | 10:35 | - | 0.0 km | 07 Min | 1 |
2 | Ramsinghpur - RMSR | 10:48 | 10:50 | 2m | 17.9 km | 15 Min | 1 |
3 | Sri Vijaynagar - SBNR | 11:05 | 11:07 | 2m | 34.0 km | 20 Min | 1 |
4 | Kalyankot - KYNT | 11:18 | 11:19 | 1m | 42.5 km | 17 Min | 1 |
5 | Raghunathgarh - RGNH | 11:26 | 11:27 | 1m | 49.2 km | - | 1 |
6 | Sarupsar Jn - SRPR | 11:34 | 11:36 | 2m | 56.0 km | 16 Min | 1 |
7 | Sardargarh - SRZ | 11:43 | 11:44 | 1m | 60.9 km | - | 1 |
8 | Sahuwala - SHWL | 11:51 | 11:52 | 1m | 65.1 km | - | 1 |
9 | Bhagwan Sar - BNSR | 11:58 | 12:00 | 2m | 72.2 km | - | 1 |
10 | Suratgarh Jn - SOG | 12:25 | End | - | 77.5 km | - | 1 |
9744 APH-SOG PASSANGER: Train Route, Schedule and Timings
Train 9744 APH-SOG PASSANGER runs from Anupgarh(APH) to Suratgarh Junction(SOG) on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Train departs from Anupgarh(APH) at 10:35 and reaches Suratgarh Junction(SOG) at 12:25. It takes 1 day to reach train 9744 from Anupgarh(APH) to Suratgarh Junction(SOG) .
APH-SOG PASSANGER 9744 train passes through 10 major stations in 1 day to reach from Anupgarh to Suratgarh Junction . It takes total of 1:50 hours journey to reach Suratgarh Junction .
In 9744 train route maximum halt time for this train is 2 minutes at
Ramsinghpur(RMSR). Train 9744 arrives at Ramsinghpur
at 10:48 and departs at
10:50. So if you want to get down from the train and buy
anything
from the station or for little fresh air. It's safe to get down at this station.
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