59709 Train Route
| S. No | Station Name & Code | Arrives | Departs | Halt Time | Distance | Avg. Delay | Day |
|---|---|---|---|---|---|---|---|
| 1 | Anupgarh - APH | Start | 16:40 | - | 0.0 km | - | 1 |
| 2 | Berore - BROR | 16:49 | 16:50 | 1m | 8.9 km | - | 1 |
| 3 | Ramsinghpur - RMSR | 16:57 | 16:59 | 2m | 17.9 km | - | 1 |
| 4 | Sri Vijaynagar - SBNR | 17:15 | 17:17 | 2m | 34.0 km | - | 1 |
| 5 | Kalyankot - KYNT | 17:26 | 17:27 | 1m | 42.5 km | - | 1 |
| 6 | Raghunathgarh - RGNH | 17:34 | 17:35 | 1m | 49.2 km | - | 1 |
| 7 | Sarupsar Jn - SRPR | 17:43 | 17:44 | 1m | 56.0 km | - | 1 |
| 8 | Sardargarh - SRZ | 17:50 | 17:51 | 1m | 60.8 km | - | 1 |
| 9 | Bhagwansar - BNSR | 18:04 | 18:05 | 1m | 72.2 km | - | 1 |
| 10 | Suratgarh Jn - SOG | 18:35 | End | - | 77.4 km | - | 1 |
59709 APH-SOG PASSANGER: Train Route, Schedule and Timings
Train 59709 APH-SOG PASSANGER runs from Anupgarh(APH) to Suratgarh Junction(SOG) on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Train departs from Anupgarh(APH) at 16:40 and reaches Suratgarh Junction(SOG) at 18:35. It takes 1 day to reach train 59709 from Anupgarh(APH) to Suratgarh Junction(SOG) .
APH-SOG PASSANGER 59709 train passes through 10 major stations in 1 day to reach from Anupgarh to Suratgarh Junction . It takes total of 1:55 hours journey to reach Suratgarh Junction .
In 59709 train route maximum halt time for this train is 2 minutes at
Ramsinghpur(RMSR). Train 59709 arrives at Ramsinghpur
at 16:57 and departs at
16:59. So if you want to get down from the train and buy
anything
from the station or for little fresh air. It's safe to get down at this station.
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