9748 Train Route
| S. No | Station Name & Code | Arrives | Departs | Halt Time | Distance | Avg. Delay | Day |
|---|---|---|---|---|---|---|---|
| 1 | Anupgarh - APH | Start | 06:35 | - | 0.0 km | 05 Min | 1 |
| 2 | Berore - BROR | 06:44 | 06:45 | 1m | 8.9 km | - | 1 |
| 3 | Ramsinghpur - RMSR | 06:52 | 06:54 | 2m | 17.9 km | 17 Min | 1 |
| 4 | Keshav Nagar Halt - KSVR | 07:02 | 07:03 | 1m | 26.7 km | - | 1 |
| 5 | Sri Vijaynagar - SBNR | 07:09 | 07:11 | 2m | 34.0 km | - | 1 |
| 6 | Kalyankot - KYNT | 07:20 | 07:21 | 1m | 42.5 km | - | 1 |
| 7 | Raghunathgarh - RGNH | 07:28 | 07:29 | 1m | 49.2 km | - | 1 |
| 8 | Sarupsar Jn - SRPR | 07:37 | 07:38 | 1m | 56.0 km | - | 1 |
| 9 | Sardargarh - SRZ | 07:44 | 07:45 | 1m | 60.8 km | - | 1 |
| 10 | Bhagwan Sar - BNSR | 07:54 | 07:56 | 2m | 72.2 km | - | 1 |
| 11 | Suratgarh Jn - SOG | 08:20 | End | - | 77.4 km | - | 1 |
9748 APH-SOG PASS SPL: Train Route, Schedule and Timings
Train 9748 APH-SOG PASS SPL runs from Anupgarh(APH) to Suratgarh Junction(SOG) on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Train departs from Anupgarh(APH) at 06:35 and reaches Suratgarh Junction(SOG) at 08:20. It takes 1 day to reach train 9748 from Anupgarh(APH) to Suratgarh Junction(SOG) .
APH-SOG PASS SPL 9748 train passes through 11 major stations in 1 day to reach from Anupgarh to Suratgarh Junction . It takes total of 1:45 hours journey to reach Suratgarh Junction .
In 9748 train route maximum halt time for this train is 2 minutes at
Ramsinghpur(RMSR). Train 9748 arrives at Ramsinghpur
at 06:52 and departs at
06:54. So if you want to get down from the train and buy
anything
from the station or for little fresh air. It's safe to get down at this station.
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