9747 Train Route
| S. No | Station Name & Code | Arrives | Departs | Halt Time | Distance | Avg. Delay | Day |
|---|---|---|---|---|---|---|---|
| 1 | Suratgarh Jn - SOG | Start | 04:25 | - | 0.0 km | 03 Min | 1 |
| 2 | Bhagwan Sar - BNSR | 04:34 | 04:35 | 1m | 5.3 km | - | 1 |
| 3 | Sardargarh - SRZ | 04:47 | 04:48 | 1m | 16.6 km | 03 Min | 1 |
| 4 | Sarupsar Jn - SRPR | 04:52 | 04:54 | 2m | 21.5 km | - | 1 |
| 5 | Raghunathgarh - RGNH | 05:03 | 05:04 | 1m | 28.3 km | - | 1 |
| 6 | Kalyankot - KYNT | 05:11 | 05:12 | 1m | 35.0 km | - | 1 |
| 7 | Sri Vijaynagar - SBNR | 05:19 | 05:21 | 2m | 43.5 km | - | 1 |
| 8 | Ramsinghpur - RMSR | 05:34 | 05:36 | 2m | 59.6 km | - | 1 |
| 9 | Berore - BROR | 05:46 | 05:47 | 1m | 68.6 km | - | 1 |
| 10 | Anupgarh - APH | 06:10 | End | - | 77.5 km | - | 1 |
9747 SOG-APH PASSENGER SPL: Train Route, Schedule and Timings
Train 9747 SOG-APH PASSENGER SPL runs from Suratgarh Junction(SOG) to Anupgarh(APH) on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday. Train departs from Suratgarh Junction(SOG) at 04:25 and reaches Anupgarh(APH) at 06:10. It takes 1 day to reach train 9747 from Suratgarh Junction(SOG) to Anupgarh(APH) .
SOG-APH PASSENGER SPL 9747 train passes through 10 major stations in 1 day to reach from Suratgarh Junction to Anupgarh . It takes total of 1:45 hours journey to reach Anupgarh .
In 9747 train route maximum halt time for this train is 2 minutes at
Sarupsar Jn(SRPR). Train 9747 arrives at Sarupsar Jn
at 04:52 and departs at
04:54. So if you want to get down from the train and buy
anything
from the station or for little fresh air. It's safe to get down at this station.
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